# Math 126 Week One Assignment

MATH 126

INTRODUCTION

A sequence of number is a list of numbers that are related to each other by a specific rule. Each number in the sequence is called a term of the sequence. The two common types of sequences are the arithmetic sequences and the geometric sequences. Arithmetic sequence is a sequence of numbers in which each succeeding terms differs from the preceding term by the same amount. This amount is known as the common difference (p272). Geometric sequence is a sequence of terms in which each term after the first term is obtained by multiplying the preceding term by a nonzero number. This number is called the common ratio (p276).

A person hired a firm to build a CB radio tower. The firm charges \$100 for labor for
the first 10 feet. After that, the cost of the labor for each succeeding 10 feet is \$25 more than the preceding 10 feet. That is, the next 10 feet will cost \$125; the next 10 feet will cost \$150, etc. How much will it cost to build a 90-foot tower?
Here is how it works:
This problem involves arithmetic sequence since the labor cost for each successive ten feet remains constant at \$25. The arithmetic sequences of the labor cost are:
10 feet charge = \$100
20 feet charge = \$125
30 feet charge = \$150
40 feet charge = \$175
50 feet charge = \$200
60 feet charge = \$225
70 feet charge = \$250
80 feet charge = \$275
90 feet charge = \$300
To compute the “n” term using the formula from page 273 of Mathematics in Our World, in the pink box. First, is to identify the following given numbers:
n = the number of all terms n = 9
d = the common difference d = 25
a1 = the first term a1 = 100
an = the last term an = a9 (to be computed)

This is the formula to find the nth term of the sequence, or the 9th term in this problem.
an = a1 + (n - 1) d
a9 = 100 + (9 – 1) 25
a9 = 100 + (8) (25)
a9 = 100 + 200
a9 = 300

The amount of last term is a9 = \$300. Now, to find the...